v^2=4v-5

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Solution for v^2=4v-5 equation:


Simplifying
v2 = 4v + -5

Reorder the terms:
v2 = -5 + 4v

Solving
v2 = -5 + 4v

Solving for variable 'v'.

Reorder the terms:
5 + -4v + v2 = -5 + 4v + 5 + -4v

Reorder the terms:
5 + -4v + v2 = -5 + 5 + 4v + -4v

Combine like terms: -5 + 5 = 0
5 + -4v + v2 = 0 + 4v + -4v
5 + -4v + v2 = 4v + -4v

Combine like terms: 4v + -4v = 0
5 + -4v + v2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -4v + -5 + v2 = 0 + -5

Reorder the terms:
5 + -5 + -4v + v2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -4v + v2 = 0 + -5
-4v + v2 = 0 + -5

Combine like terms: 0 + -5 = -5
-4v + v2 = -5

The v term is -4v.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4v + 4 + v2 = -5 + 4

Reorder the terms:
4 + -4v + v2 = -5 + 4

Combine like terms: -5 + 4 = -1
4 + -4v + v2 = -1

Factor a perfect square on the left side:
(v + -2)(v + -2) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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